Chess for pacifists
By Steve Giddins
Do you ever feel there is too much conflict in the world? If you do, then OTB
chess – the recent Kazan Candidates aside – is possibly not the ideal
thing for you, since chess is, after all, a war game. But here in the world
of chess problems, we have a niche for those of you who find the sight of White
and Black trying to beat each other's brains out unpalatable– the wonderful
world of helpmates.
In a helpmate, the two sides cooperate, in a mutual quest to create something
beautiful. Black generally moves first, and helps White to mate the black king
in the required number of moves. The fact that the two sides are working together
allows many beautiful and paradoxical ideas to be shown.
Peter Knienst,
4th Prize Kennst du die Bibel? 1966

Helpmate in four
Here is a very nice, but not too complicated example. Black moves first and
helps White to give mate on his fourth move. If you want a clue, here is one:
if the BK stood on e4 and the Rf1 on f4, the position would already be mate,
so it is just a matter of arranging that!
So, how did you get on? If you struggled, don't worry – practice makes
perfect, just as Übung macht den Meister in Germany, and after
a bit of practice, you will soon get the hang of helpmates. After the clue I
gave you, it looks as though it should be a simple way to arrange the mating
pattern, but in fact, there is only one way (of course!), and it is very pretty.
The solution runs (I remind you once again, Black moves first): 1.Kf2
Ng7 2.Ke3+ N3f5+ 3.Ke4 Nh5 4.Rf4 5 Nhg3#
Isn't that nice? The two white knights have to swap places in the course of
the solution!

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1...Kf2 2.Ng7 Ke3+ 3.N3f5+ Ke4 4.Nh5 Rf4 5.Nhg3#
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Peter Knienst,H | - | | - | | | | 4th Pr Kennst du die Bibel? 1966 | |
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And now another helpmate, by a composer whose name we met in my first column:
Matti Myllyniemi, Satakunan Kansa 1968

Helpmate in two – four solutions
One thing which will strike you is the stipulation, which refers to four solutions.
This may seem to contradict what I stated much earlier, namely that the solution
to a problem must be unique. For most problems, especially direct mates, this
is indeed the case – a second solution, especially one that is unintended by
the composer, would be referred to as a cook and is regarded as a fatal
flaw. But multiple solutions are sometimes intended, and in helpmates, they
are especially common. In most cases, there will be a strong thematic link between
the different solutions, as is the case here.
Here it is a helpmate in two, so we are looking for a sequence which runs:
B moves, W moves, B moves, W mates. Have a look and try to solve the problem,
before reading on.
So, how did you get on? If you struggled, don't worry – practice makes
perfect, just as Ubung macht den Meister in Germany, and after a bit
of practice, you will soon get the hang of helpmates. The first solution (remember,
Black moves first) is 1.Kd5 Qe7 2.Qc4 Be4#. Keep that mating pattern
in mind, and see if you can find the second solution. No luck? It is 1.Bc3
Qd6 2.Qb3 Bd3#. Yes, indeed – the same mate as the first solution, but moved
one square down the diagonal, towards the South West. You should be getting
the idea by now, so try finding solution three. Yes, that's right: 1.Bb2
Qc5+ 2.Kb3 Bc2# – the same mate again, shifted another square along
the diagonal! The fourth solution is slightly trickier to spot, but is worth
seeing – 1.Qg2+ Kh4 2.Qd5 Bd3#. Look at that final
mate again – it is the same mating position as the others, but this time rotated
through 90%!
A wonderful little problem, with just six pieces on the board. And the alert
reader may have spotted something else about it: as the stipulation above the
diagram makes clear, this little gem did not even get a prize – they can be
tough chaps to please, these problem judges!

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1...Kd5 1...Bc3 2.Qd6 Qb3 3.Bd3# 1...Bb2 2.Qc5+ Kb3 3.Bc2# 1...Qg2+ 2.Kh4 Qd5 3.Bd3# 2.Qe7 Qc4 3.Be4#
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Myllyniemi | - | Helpmate in 2,4 | - | | | | Satakunan Kansa 1968 | |
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The next position is another multi-solution helpmate, but with a twist:
Narayan Shankar Ram,
6th Honourable Mention, The Problemist 1986

Helpmate in two – duplex
This is a duplex, which in this case has nothing to do with split-level apartments
in desirable residential areas. In a duplex helpmate, we have two problems in
one: in one solution, Black moves first and helps White to checkmate him, and
in the other solution, starting from the same position, White moves first and
helps Black mate him! Once again, have a go at solving for yourself, before
you read on. I suggest you start with the Black to move solution.
Although only two moves long, the solution is not a "gimme": 1.Ba5
Be4 2.Rf5 Bc6#. Let us look at exactly what happens in this solution: Black's
first move self-blocks one of his king's flights. White's first move unpins
a black piece, namely the Rf4. Black's second move in turn unpins a white piece
(the Be4), and White's second move sees that unpinned piece give double check
and mate.
Now watch what happens in the duplex solution, where White moves first and
helps Black give mate: 1.Rh5 (self-block), Re4 (unpins WB) 2.Bc4
(unpins BR) Re6 mate (double check and mate)!
Absolutely beautiful! The strategy in the two phases is exactly mirrored, a
perfect exploitation of the duplex twinning method.

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1...Ba5 1...-- 2.Rh5 Re4 3.Bc4 Re6# 2.Be4 Rf5 3.Bc6#
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Narayan Shankar Ram | - | Helpmate in 2,d | - | | | | 6th HM, The Problemist 1986 | |
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Self-immolation on the chessboard
Now is time to introduce another problem genre: the selfmate. In a selfmate,
we are back to conflict again, but with a difference: White moves first, but
instead of trying to mate Black, he instead tries to force Black to mate
him! Black is trying to avoid mating White. It is the chessboard equivalent
of the old joke about the masochist and the sadist: the masochist says "Hurt
me, hurt me!" and the sadist says "No, I won't!"
Our first selfmate this month, but it is a beauty, by a composer more famous
for his endgame studies, but who was also a prolific and brilliant problemist:
Leonid Kubbel - 1st Pr Jas 1935

Selfmate in three
It is in the nature of selfmates that Black will usually have very few legal
moves – after all, in order to force him down a narrow path to giving mate,
White will inevitably need a great deal of control. Looking at the position,
we can see the germ of an idea or two. For example, can we arrange for cxb5
to be mate? It looks unlikely, because the Rb3 and Nb5 can always capture on
b5, whilst if the rook moves away in advance, the white king will have the square
b3. Another idea is to arrange c6-c5 as discovered check and mate, but that
seems even more unlikely, as White has two pieces able to interfere on b5, and
the Nc7 attacks the bishop. So, do you think it impossible? Oh ye of little
faith!
We kick off with 1.Rd8! This gives Black three legal moves. Let's start
with 1...Bg6. Now we play 2.Qc1+ Bc2 (forced) 3.Nb5 and,
lo and behold, Black's only legal move is 3 ..cxb5#, which, thanks to
the fact that we have cunningly managed to force Black to pin the Rb3, is mate!
That's pretty neat in itself, but there's more. Black can instead try 1...Bf7.
But now we have another way of forcing him to take control of b3: 2.Nxe6+
Bxe6 and now the trap is sprung: 3.Rb5+ cxb5#.
Finally, we turn to Black's other legal move, 1...Bd7. Now there is
no chance of forcing him to take control of b3, but instead, we have another
striking idea: 2.Qd4+! Kxd4 3.Kb4 and now, with his bishop pinned and
his king immobile, Black's only remaining legal move is 3...c5#.

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1.Rd8! Bg6 1...Bf7 2.Nxe6+ Bxe6 3.Rb5+ cxb5# 1...Bd7 2.Qd4+! Kxd4 3.Kb4 c5# 2.Qc1+ Bc2 3.Nb5 cxb5#
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L Kubbel | - | 1st Pr Jas 1935 | - | | | | Selfmate in 3 | |
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Fantastic, I hope you agree? And surely a welcome change from spending all
of one's chess leisure time trying to find a microscopic edge on move 25 of
the Russian Defence? If you agree, here is another selfmate to get your choppers
into:
Knud Hanneman, Tijdschrift N I S B 1931

Selfmate in four
Here, the basic mating idea looks clear enough – somehow, we have to
arrange to force Rxd8 mate. But how exactly? Over to you! But what's this –
you want a clue? Well, if you are a German speaker, I can just whisper the word
Allumwandlung, and that should be all you need. And for those of you
who do not speak German, I could just be nasty and recommend Google Translate,
but instead I will ask you a question: how many pieces can a pawn on the 7th
promote to in a game of chess?
I hope the clue was enough, but don't despair if it wasn't! The spectacular
solution is 1.h8Q+ Kg6 2.g8R+ Kxf7 3.e8B+ Ke6 4.d8N+ Rxd8#.
Yes, indeed – the white pawns promote in turn to each of the four possible
pieces. This theme is a common one in problems (and even in some studies), known
by the German word Allumwandlung, or "all promotions".
Well, that is all for now. I will be back in a couple of weeks, with more on
the wonderful world of the chess problem. See you then!

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1.h8Q+ Kg6 2.g8R+ Kxf7 3.e8B+ Ke6 4.d8N+ Rxd8#
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Knud Hanneman,S | - | | - | | | | Tijdschrift N I S B 1931 | |
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