Keymer edges out Liang to win Kramnik Challenge

by Carlos Alberto Colodro
8/16/2021 – Two wins and a draw on the fourth day of action granted Vincent Keymer tournament victory at the Kramnik Challenge for young stars. Most importantly, Keymer beat Awonder Liang in the penultimate round — Keymer and Liang would end the event tied in points, and the result in their direct encounter was the tiebreak decider that gave the German prodigy first place.

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A crucial win

Awonder Liang finished day 3 of the Kramnik Challenge in sole first place, with Vincent Keymer standing a half point behind. The fight for tournament victory was fierce on Sunday, as both players kicked off with wins. In the penultimate round, they were paired against each other, and Keymer had the white pieces.

In a tough strategic battle, Keymer got a positional plus. On move 36, the German simplified into an advantageous position with rooks, same-coloured bishops and queens.

 
Keymer vs. Liang - Round 14

35.f3 Nc5 36.Bxc5, and Black cannot capture with the rook — after 36...Rxc5 White has the killer 37.e4, when 37...fxe4 is bad due to 38.Rd8+ Kh7 39.Qxe4+ and Black is doomed.

 
Analysis diagram

Thus, Liang had to play 36...bxc5, and White got a strong initiative with his rook infiltrating along the d-file and the bishop finding good coordination with the queen to attack along the light squares.

 

This position was reached four moves later. After 40.h5, there was no way to save Black’s position. Liang resigned soon after.

 
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1.Nf3 Nf6 2.c4 e6 3.b3 b6 4.g3 Bb7 5.Bg2 d5 6.Bb2 Be7 7.cxd5 exd5 8.0-0 0-0 9.e3 A14: English Opening: 1...e6 with b3 by White. Nbd7 10.Nc3 Re8 11.Rc1 The position is equal. a6
12.Re1N Predecessor: 12.Ne2 Bf8 13.Re1 Rc8 14.Bh3 c5 15.Bxf6 Nxf6 16.Bxc8 Bxc8 17.d3 Bg4 18.Kg2 1-0 (61) Anton Guijarro,D (2685)-Kovalev,V (2662) Moscow 2019 12...Nc5 13.d3 Ne6 14.Re2 Rc8 15.Rec2 c5 16.d4 Rc7 16...c4= 17.Ne2 17.Na4± 17...Ne4 18.Ne5 f5 19.Nd3 Bd6 20.Nef4 Nxf4 21.gxf4 Qe7 22.Ne5 Rec8 23.h3 Qe6 24.Qe2 Qe7 25.Kh2 Qe6 26.a4 Bxe5 26...Qe7= 27.dxe5± Hoping for f3. c4 28.Bd4 a5 29.bxc4 Rxc4 30.Rxc4 dxc4 31.Rb1 Rc6 32.Qc2 32.Qh5± 32...Bc8 33.Bf1 33.Rd1± 33...Ba6 33...c3= remains equal. 34.Rd1! h6
35.f3! Nc5 36.Bxc5 bxc5 37.Rd8+ Kh7 38.h4 Strongly threatening h5. c3?
38...Qe7 39.Qxf5+ g6 39.Bh3!+- g6 40.h5 Black must now prevent hxg6+. Rb6? 40...Qe7 41.Ra8 Bb7 41.hxg6+ Kg7 42.Qxc3 Bb7 43.Rd6 White mates. Rxd6 44.exd6+ Kxg6 45.Qxc5 Bc8 46.e4 Kf7 47.Bxf5 Weighted Error Value: White=0.13/Black=0.48
1–0
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WhiteEloWBlackEloBResYearECOEventRnd
Keymer,V2602Liang,A25871–02021Kramnik Challenge 202114.6

So, going into the final round, Keymer was a half point ahead of Liang and knew that he would be granted tournament victory if they finished tied in points. Liang had white against Balaji Daggupati while Keymer was paired up against Dinara Saduakassova with the black pieces. At some point, both players had losing positions!

Keymer was a piece down in an endgame.

 
Saduakassova vs. Keymer - Round 15

The conversion is not at all trivial, but of course only White can win from this position. Keymer defended stubbornly and saved an 86-move draw. Meanwhile, Liang in fact tricked his younger compatriot and got a full point to climb to shared first place.

Both dramatic games are presented in the replayer below.

 
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1.e4 0 c5 0 2.Nc3 4 Nc6 3 3.Bb5 1 Nd4 1 4.Nf3 0 e6 2 5.0-0 2 a6 2 6.Bd3 2 Nc6 2 7.e5 16 Nge7 0 8.Re1 3 Ng6 1 9.b3 1 d6 24 10.exd6 6 Bxd6 0 11.Bb2 1 0-0 9 12.Ne4 1:03 Be7 0 13.Ng3 1 Bf6 52 14.Qc1 35 Nd4 1:44 15.Nxd4 2 Bxd4 2 16.Bxd4 17 Qxd4 28 17.Re4 18 Qf6 0 18.Re3 11 b6 16 19.Rb1 26 Bb7 4 20.b4 2 cxb4 1:12 21.Rxb4 11 b5 21 22.Qd1 1:43 Rad8 0 23.a4 1:44 Rd4 28 24.Rxd4 34 Qxd4 0 25.axb5 1 axb5 2 26.Bxb5 7 Bxg2 36 27.c3 2 Qd5 0 28.c4 3 Qb7 1 29.f3 35 Nh4 17 30.Kf2 2 Rd8 18 31.d4 0 Qb6 14 32.Ne2 15 e5 12 33.Qd3 25 exd4 1:20 34.Re4 3 Nxf3 1 35.Nf4 7 Bh1 28 36.Nh5 0 Qh6 14 37.Qe2 1 Qd2 1:00 38.Ng3 2 Qxe2+ 1 39.Kxe2 1 d3+ 7 40.Kd1 2 Ng5 6 41.Re5 0 Bf3+ 3 42.Kd2 2 f6 12 43.Re7 1 Kf8 7 44.Re3 4 h5 0 45.h4 1 Nf7 12 46.Rxf3 3 Ne5 0 47.Re3 3 Rd4 1 48.Re4 9 Nf3+ 1 49.Ke3 8 Rd8 0 50.Kxf3 5 d2 2 51.Ba4 0 d1Q+ 5 52.Bxd1 1 Rxd1 0 53.Nxh5 1 Kf7 5 54.Ng3 2 g6 0 55.Ne2 7 Rd3+ 12 56.Re3 2 Rd8 1 57.Rc3 1 Rh8 1 58.Kg3 7 Re8 4 59.Nd4 8 Re4 0 60.Nb5 1 Ke6 5 61.c5 1 Kd7 9 62.c6+ 2 Kc8 4 63.Nd6+ 1 1–0
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WhiteEloWBlackEloBResYearECOEventRnd
Liang,A2587Daggupati,B24291–02021Kramnik Challenge 202115.3
Saduakassova,D2483Keymer,V2602½–½2021Kramnik Challenge 202115.4

Kramnik Challenge 2021

Final standings (with team points tallied)

Endgame analysis by GM Karsten Müller

In his daily instructive analysis from the youth tournament, endgame specialist Karsten Müller analyses a position with rooks and bishops of opposite colours. French prodigy Marc Andria Maurizzi twice failed to play the winning move with black against Christopher Yoo.

 
Yoo vs. Maurizzi - Round 13

The immediate 52...h3+, dubbed ‘the sting of the scorpion’ by GM Müller, wins for Black. Maurizzi played 52...Kxg4 and the tough struggle continued. A couple more imprecisions led to a 75-move draw. Do not miss the full analysis by our in-house specialist!

 
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1.e4 c6 2.Nf3 d5 3.d3 Bg4 4.h3 Bxf3 5.Qxf3 e6 6.d4 Nf6 7.exd5 cxd5 8.Bd3 Nc6 9.c3 Be7 10.0-0 0-0 11.Qe2 a6 12.a4 Qc7 13.f4 Bd6 14.g3 h5 15.Qf3 g6 16.Be3 b5 17.axb5 axb5 18.Nd2 b4 19.c4 dxc4 20.Nxc4 Nd5 21.Rxa8 Rxa8 22.f5 Nxe3 23.Nxe3 exf5 24.Nxf5 Rf8 25.Be4 Nxd4 26.Nxd4 Qb6 27.Kh1 Qxd4 28.Bd5 Kg7 29.b3 f5 30.Re1 Be5 31.Bc4 Qc3 32.Re3 Qa1+ 33.Kg2 Qb2+ 34.Re2 Qc3 35.Re3 Qd4 36.Re2 Qc3 37.Re3 Qd2+ 38.Re2 Qd4 39.Qb7+ Kh6 40.Qxb4 Rb8 41.Qe7 Bf6 42.Qe3+ Qxe3 43.Rxe3 h4 44.g4 fxg4 45.hxg4 Ra8 46.Kh3 Ra1 47.Re6 Kg5 48.Re2 Rg1 49.Rg2 Rh1+ 50.Rh2 Rc1 51.Rd2 Be5 52.Kg2 "The sting of the scorpion". Opposite colored bishops have two faces. Pure opposite colored bishop endings have a large drawish tendency, but if more pieces are on the board they favor the attacker: Kxg4? Now White should be able to defend thanks to his blockade on the light squares. The sting of the scorpion 52...h3+ wins due to 53.Kxh3 53.Kf2 h2 54.Bd5 Kxg4 55.Ra2 h1Q-+ 53...Rh1+ 54.Kg2 Rh2+ 55.Kf3 Rxd2-+ 53.Be6+ Kg5 54.Kf3? This again runs into the sting of the scorpion. 54.Rd3 defends. 54...Rc3+? Black again misses 54...h3! 55.Bxh3 Rc3+ 56.Ke4 Rxh3 57.Kxe5 Re3+! 58.Kd4 Rxb3 59.Rg2+ Kf5 60.Rf2+ Kg4 61.Rg2+ Rg3-+ 55.Ke4 Bg3 55...Bc7 is met by 56.Rd3 Rxd3 57.Kxd3= 56.b4? Now it gets very delicate, and I cannot say whether Black can win or not. 56.Rd3= was called for and defends. 56...Kf6! 57.Bh3 Be1? This just loses valuable time. 57...Rb3!? 58.Rd3 58.b5 Rb4+ 59.Rd4 Rxb5 58...Rxb4+ 59.Rd4 Rb1 gives Black winning chances in both cases. The pure endgame would be a clear draw, but with rooks, matters are different. 58.Rd6+ Kg5 59.Rd5+ Kf6 60.Rd6+ Ke7 61.Rd3 Rc2 61...Rc4+ 62.Rd4 Rxd4+ 63.Kxd4 Bxb4 64.Ke4= 62.Re3 Rc1 Of course not 62...Bxb4?? 63.Kd3++- 63.Kd5+ Kf6 64.b5 Bg3 65.b6 Rh1 66.Bc8 Bf4 67.Rf3 Kg5 68.b7 Rb1 69.Rc3 Rb2 70.Ke4 Bg3 71.Rc5+ Kf6 72.Rc6+ Kg5 73.Rc5+ Kf6 74.Rc6+ Kg5 75.Rc5+ ½–½
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WhiteEloWBlackEloBResYearECOEventRnd
Yoo,C2466Maurizzi,M2488½–½2021B10Kramnik Challenge 202113.7

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Carlos Colodro is a Hispanic Philologist from Bolivia. He works as a freelance translator and writer since 2012. A lot of his work is done in chess-related texts, as the game is one of his biggest interests, along with literature and music.

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