Danzhou Masters: Yu Yangyi comes out on top

by Aditya Pai
8/4/2018 – Scoring 4½/7, tournament's top seed, GM Yu Yangyi bagged the title prize of the 9th Hainan Danzhou Super Grandmaster tournament. In the final round, the race for the title was between Yu Yangyi and his countryman Bu Xiangzhi. Going for a comfortable draw in the Petroff, Yu put the onus of catching up on his rival who was half-a-point behind. Bu was never really in a position to win his game but Fedoseev, Bu's opponent, surprisingly pulled out a win at the last moment to score his first win of the event. Le Quang Liem and Wei Yi also scored impressive wins in the finale.

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Round 7

After a stormy penultimate round, the battle for the title of the 9th Hainan Danzhou Masters was between the overnight tournament leader, Yu Yangyi and his compatriot Bu Xiangzhi. Bu was half-a-point behind the leader and had to win at all cost to remain in contention.

Yu Yangyi, on the contrary, could afford to take things calmly. He had the luxury of going for a solid draw and putting the onus of catching up on his rival. And that is what he did.

Sam Shankland vs Yu Yangyi

Yu had the black pieces against Sam Shankland in the final round and went for his favourite Petroff Defence. As is the case in most Petroffs, the position reached out of the opening was rather bland. By the 21st move, a dead equal endgame with rooks and bishops of opposite colours was reached. The game went on for 17 more moves but the result of the game was never in doubt. 

Sam Shankland and Yu Yangyi during their final round game at the Danzhou Masters

Yu Yangyi decided to go for a quiet draw in the final round | Photo: Official website

 
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1.e4 e5 2.Nf3 Nf6 3.d4 Nxe4 4.Bd3 d5 5.Nxe5 Nd7 6.Nxd7 Bxd7 7.0-0 Bd6 8.Qh5 Qf6 C43: Petroff Defence: 3 d4 9.Nc3 9.Be3 0-0-0 10.Nc3 Nxc3 11.bxc3 Qe6 12.Rfe1 f6 13.Bd2 Qg8 14.Rab1 Kb8 15.h3 b6 16.Ba6 1-0 (41) Ivanchuk,V (2728)-Giri,A (2772) Tbilisi 2017 9...Qxd4 10.Be3 Qe5 11.Qxe5+ Bxe5 12.Nxd5 Nf6 13.Rae1 LiveBook: 15 Games. And now Bd4 would win. Nxd5 14.Bd4 0-0-0 15.Bxe5 Nb4 16.Bxg7 Nxd3 17.cxd3 Rhg8N 18.Be5 Bc6 19.f3 Rxd3 20.Bg3 Re8 21.Rxe8+ Bxe8= Endgame KRB-KRB 22.Rc1 Bc6 23.Be5 Kd7 24.Rc4 Rd5 25.Bc3 Rf5 26.Rd4+ Ke7 27.a3 Bd7 28.Kf2 c5 29.Re4+ Be6 30.Ke3 Rd5 31.h3 b5 32.g4 f5 33.Rf4 fxg4 34.fxg4 h5 35.gxh5 Rxh5 36.h4 Rf5 37.Rxf5 Bxf5 38.h5 Be6 Precision: White = 63%, Black = 49%. ½–½
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WhiteEloWBlackEloBResYearECOEventRnd
Shankland,S2727Yu,Y2762½–½20189th Hainan Danzhou GM 20187

Vladimir Fedoseev vs Bu Xiangzhi

A draw in Yu Yangyi’s game meant Bu Xiangzhi had a chance to catch up with the tournament leader. However, Bu’s own position did not hold much promise.  Within the first 25 moves in a Queen’s Indian Defence, the game had reached a rook and pawn endgame with five pawns for each side. 

 
Vladimir Fedoseev vs Bu XIangzhi
Position after 25...fxe6

Although the position looks more or less equal, Fedoseev is in the driver’s seat here. Despite material equality, black is under some pressure due to his weak pawns and passive rook. White managed to net a pawn here after 26.Rd6 Kf7 27.Rd7+ Kf6 and 28.Ra7. It took some time in the ensuing endgame for Fedoseev to convert the game but by move 58, he had secured his first win of the tournament. 

Bu Xiangzhi during his final round game against Samuel Shankland at the Danzhou Masters

Vladimir Fedoseev won his first game of the tournament against Bu Xiangzhi | Photo: Official website

 
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1.d4 Nf6 2.c4 e6 3.Nf3 b6 4.a3 Bb7 5.Bf4 d5 6.cxd5 exd5 7.Nc3 Bd6 8.Bxd6 Qxd6 9.Rc1 LiveBook: 19 Games. And now Nb5 would win. E12: Queen's Indian: Unusual White 4th moves, 4 a3, 4 Nc3 Bb7 5 a3 and 4 Nc3 Bb7 Qe7 9...a6 10.g3 0-0 11.Bg2 Nbd7 12.0-0 Rfe8 13.e3 Rac8 14.Ne1 c5 15.dxc5 bxc5 16.Nd3 Nb6 1/2-1/2 (109) Nakamura,H (2779)-Dubov,D (2660) Doha 2016 10.g3 0-0 11.Bg2 The position is equal. Nbd7 12.0-0 c5 13.e3N Predecessor: 13.Re1 Rfd8 1/2-1/2 (24) Piket,J (2410)-Van der Wiel,J (2555) Leiden 1986 13...a6 14.Nd2 Rfd8 15.Re1 Rac8 16.e4 dxe4 17.Ncxe4 Nxe4 18.Nxe4 Bxe4 19.Bxe4 Qd6 20.dxc5! Qxd1 21.Rexd1 Hoping for Bf5. Nxc5 22.Bf5 Rb8 23.b4 Black is under pressure. Ne6 24.Bxe6 Rxd1+ Better is 24...fxe6 25.Rxd8+ Rxd8 25.Rxd1± fxe6 Endgame KR-KR 26.Rd6 Kf7 27.Rd7+ Kf6 28.Ra7 a5 Black should play 28...b5 29.bxa5± bxa5 30.Rxa5 Rb3 31.a4 Ra3 32.Ra8 g5 33.Kf1 Ra1+ 34.Ke2 Kf5 35.Kf3! g4+ 36.Ke3 36.Kg2!+- 36...e5 37.a5 Strongly threatening a6. Ra3+ 38.Ke2 Ke4 39.a6! Ra1 39...h6± was called for. 40.a7+- h6 41.Kd2 Ra2+ 42.Ke1! Ra1+
43.Ke2! Ra2+ 44.Kf1 Ra1+ 45.Kg2 Ra2 46.h4 h5 47.Rh8 Rxa7 48.Rxh5 Rg7 49.Kf1 Rg8 50.Ke2 Rg7
51.Rh8! Kf5 52.Rf8+ Ke6? 52...Ke4± is a better chance. 53.Re8 Rc7 53.f3 White is clearly winning. Ke7 54.Ra8 Threatens to win with Ra7+. Kf6 54...Ke6 55.Ra4 gxf3+ 56.Kxf3 Kd5 55.Ra4 gxf3+ 56.Kxf3 Rf7 57.Ke4 Kg6 58.Ra5 Precision: White = 87%, Black = 38%.
1–0
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WhiteEloWBlackEloBResYearECOEventRnd
Fedoseev,V2707Bu,X27121–020189th Hainan Danzhou GM 20187

Vidit Gujrathi vs Le Quang Liem

Le Quang Liem had an extra pawn against Vidit Gujrathi for the most part of the game. Vidit, on the other hand, had the initiative and a better pawn structure.  On the 64th move, by when the tide had already begun to turn in Le’s favour, Vidit cracked and made back-to-back errors.

 
Vidit Gujrathi vs Le Quang Liem
Position after 64.Kh3

Vidit had chased the king all the way from the kingside to its current post where it now looked safe. White had no checks and the discovered attack on the queen didn’t lead anywhere. Unwilling to take on c5 and give up the pin on the knight — which was the best way to proceed — Vidit decided to go with his king to h3. Now after 64…Ne5 65.Nxe5 Qxe2, the white king suddenly looks exposed. Vidit tried 66.Nf7+ but after 66…Kc6 (not allowing any checks) 67.Kg2 g4, Black just had an overwhelming advantage.

Le Quang Liem during the seventh round of Danzhou Masters

Le Quang Liem finished on a high note with two consecutive wins in the last two rounds | Photo: Official website

 
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1.d4 Nf6 2.c4 e6 3.Nc3 Bb4 4.Qc2 d5 5.cxd5 exd5 6.Bg5 h6 7.Bh4 c5 8.dxc5 E35: Nimzoindisch (4.Dc2) 0-0 9.e3 Be6 10.Nf3 Nbd7 11.Be2 Rc8 LiveBook: 20 Partien 12.c6 bxc6 13.0-0 Qa5
14.Nd4N Vorgänger: 14.Rac1 c5 15.Rfd1 Rfe8 0-1 (120) Shirov,A (2701)-Adams,M (2752) Bilbao 2014 14...Bd6 15.Rfd1 Rfe8 16.Rac1 c5 17.Nxe6 fxe6 18.e4 c4 19.exd5 exd5 Mit der Idee ...Lf4. 20.Qf5 20.g3 20...Kh8= 21.Bf3 Be5 22.Bg3 22.Bxd5? Bxc3 23.Be6 23.bxc3? Rc5-+ 23...Qxf5-+ 22...Bxg3 23.hxg3 Re5 23...Rc5!? 24.Qf4 24.Nxd5 Re5= 24.Bxd5? Nb6-+ 24...Ne5= 24.Qf4 Rce8 25.b3 Nb6 26.Qd4 R5e7 27.g4 27.Bxd5? Nfxd5 28.Nxd5 Nxd5-+ 27.Nxd5? Nbxd5 28.Qxc4 Rc7-+ 27...Rc8 28.Ne2 28.Bxd5? Nfxd5 29.Nxd5 Nxd5-+ 28.Nxd5? Nbxd5 29.Rxc4 29.g5? hxg5 30.Bxd5 Nxd5-+ 29...Rxc4-+ 28...Qxa2 29.Nf4 Rec7 Günstiger ist 29...Ree8= 30.bxc4 30.Qe5! 30...Rxc4 31.Rxc4 Qxc4 32.Qe5 Droht Sg6+ und aus. Re8 33.Qf5 Qc3 34.g5 hxg5 35.Qxg5 Re1+ 36.Rxe1 Qxe1+ 37.Kh2 d4 38.Be2 Droht Matt per Se6. Qb4 38...Kg8!= bleibt in der Remisbreite. 39.Ng6+± Weiss hat starke Kompensation. Kg8 40.Qe5! Kf7 40...Qd2± 41.Nf4 Kh7 41.Qc7+!+- Kg8 41...Kxg6? 42.Bd3+ Ne4 43.Qf4+- 43.Bxe4+ Kf6± 42.Ne7+ 42.Qxa7?! Qd6+ 43.Kg1 d3± 42.Bd3!+- Schwarz muss nun Dd8+ beachten. Nbd7 43.Qc6 43.Qxa7 Qb8+ 44.Qxb8+ Nxb8± 42...Kf8 43.Ng6+ 43.Nf5± Ne8 44.Qxa7 43...Kg8+- 44.Qb8+ Jedoch nicht 44.Qxa7?! Nbd7± 44.Bd3!+- Nbd7 45.Qc6 45.Qxa7 Qb8+ 46.Qxb8+ Nxb8± 44...Kf7 45.Bd3 Lieber 45.Nh8+ Ke6 46.Qxa7 45...Qc5 45...a5!= 46.Nf4 Besser ist 46.Qxa7+± Nbd7 47.Qa2+ Ke8 48.g3 46...Nbd7 Schwarz steht aktiver. 47.Qb3+ Ke7 48.Qe6+ Kd8 Droht stark ...De5. 49.g3 Nf8 und nun wäre ...Dh5+! stark für Schwarz. 50.Qf7 Qe7 51.Qb3 Beabsichtigt Db8+ und Matt. N6d7 Ein No Go ist 51...Ng4+?! 52.Kg2± 52.Qd5 Und Da8+ würde nun gewinnen. Qc5 Weiss sollte ...Dxd5 verhindern. 53.Qa8+ Ke7 54.Qe4+ Ne5 55.Be2 zielt auf Sd3 ab. Kd6 56.Qa8 Ned7 57.Bg4 g5 58.Nd3 Qb5 59.Qe4 Qd5 60.Qe1 a5 61.Qc1 Qb5 62.Be2 Ne6 63.Qa3+
63.Qd2= hält das Gleichgewicht. 63...Nec5! 64.Kh3 64.Nxc5 Qxc5 65.Qb3 64...Ne5-+ 65.Nxe5 65.Nxc5 Qxc5 66.Qb3 65...Qxe2 66.Nf7+?
66.Ng4 a4 67.Qb4 66...Kc6! 67.Kg2 g4 68.Nd8+ Kb5 69.Qa1 Qe4+ 70.Kg1 d3 71.Nf7 Qd5 72.Qb2+ Ka6 72...Nb3 73.Nd6+ Kb4 74.Qg7 Qxd6 75.Qg8 d2 76.Qxg4+ Qd4 77.Qd1 Qa1 78.Qxa1 Nxa1 79.Kg2 d1Q 80.Kh3 a4 81.g4 Nc2 82.Kh4 a3 83.Kg5 a2 84.Kf4 a1Q 85.Kg3 Qe5+ 86.f4 Qg1+ 87.Kh4 Qh2# 73.Qf6+ Ne6 Schwarz setzt Matt. 74.Qc3 d2 75.Qc8+ Ka7 Precision: Weiß = 38%, Schwarz = 47%.
0–1
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WhiteEloWBlackEloBResYearECOEventRnd
Vidit,S2718Le,Q27280–120189th Hainan Danzhou GM 20187

Jan-Krzysztof Duda vs Wei Yi

Jan-Krzysztof Duda and Wei Yi discussed the Mikenas variation of the English Opening. Wei was very well prepared for the game. Deviating from known theory on his 8th turn, he went on to get a slight advantage early in the game. Although queens were off the board, Wei, with his extra space and double bishops, exerted considerable pressure on Duda’s position. Duda fought hard to restore equilibrium but Black’s advantages turned out to be too difficult for him to deal with. 

 
Jan-Krzysztof Duda vs Wei Yi
Position after 33...Bh6+

On his 33rd move, Duda allowed a deadly check on h6 and after 34.Ng5 f4+ 35.gxf4 exf4+ 36.Kxf4 Rd2, realized that the bishop did not have a decent square. After 37.Re3 or Ke3 Black has 37…Rxa2 after which the a-pawn is too strong. Duda gave up a piece here with 37.Bxh5 but did not survive for too long in the resulting endgame. 

Jan Krzysztof Duda playing against Wei Yi in the final round of the Danzhou Masters

Wei Yi came well prepared for his final round game against Jan Krzysztof Duda | Photo: Official website

 
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1.c4 Marin,M e6 2.Nc3 Nf6 3.e4 d5 4.e5 d4 5.exf6 dxc3 6.dxc3 A18: English Opening: Flohr-Mikenas System (1 c4 Nf6 2 Nc3 e6 3 e4) Qxd1+ 7.Kxd1 gxf6 8.g3 LiveBook: 4 Games. The position is equal. Nc6N Predecessor: 8...Bd7 9.Bg2 Bc6 10.Bf3 Bxf3+ 11.Nxf3 Nc6 12.Ke2 Ne5 13.Nxe5 fxe5 1-0 (57) Jobava,B (2661)-Wojtaszek,R (2722) Gjakova 2016 CBM 173 [Marin,M] 9.Ke2 h5 10.b3 a5 11.Bg2 a4 aiming for ...axb3. 12.b4 Ne5 13.c5 Bd7 White must now prevent ...Bb5+. 14.c4 0-0-0 15.Bb2 Bg7 16.Bxe5 fxe5 17.Rd1 f5 18.Nf3 18.h4 18...Bf6! 19.h4 Bc6 20.Rxd8+ Rxd8 21.Rc1 e4 22.Ng5 Rd4 ...Rxc4! is the strong threat. 23.Bf1 Bd7 24.Ke3
24...e5 Black should play 24...Kd8! 25.Be2= Be8 26.Ne6 Rd7 27.Rd1 27.a3= keeps the balance. 27...a3 And now ...Rxd1 would win. 28.Rb1 28.Rg1 28...Bf7-+ 29.Ng5 Bg6 30.Rd1 Rd4 31.Nh3 Bg7 32.Rc1 32.Ng5 32...Kd7 33.Rc3 Bh6+ 34.Ng5?
34.f4 exf3+ 35.Kxf3 34...f4+! 35.gxf4 exf4+ 36.Kxf4 Threatens to win with Ke3. Rd2! 37.Bxh5 Bxh5 38.Rxa3 Rxf2+ 39.Kxe4 39.Kg3 Re2 40.Kf4 39...Bg6+ 40.Kd4 Re2 41.c6+ Kxc6 42.b5+ Kb6 ( -> ...Bg7+) 43.Kd5 c6+ 44.Kd4 Precision: White = 42%, Black = 78%.
0–1
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WhiteEloWBlackEloBResYearECOEventRnd
Duda,J2737Wei,Y27290–120189th Hainan Danzhou GM 20187

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Aditya Pai is an ardent chess fan, avid reader, and a film lover. He holds a Master's in English Literature and used to work as an advertising copywriter before joining the ChessBase India team.

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