[Event "FIDE Women's World Teams"]
[Site "Mardin TUR"]
[Date "2011.12.20"]
[Round "3.16"]
[White "Khurtsidze, Nino"]
[Black "Hoang, Thi Nhu Y"]
[Result "0-1"]
[ECO "A12"]
[WhiteElo "2440"]
[BlackElo "2218"]
[Annotator "Mueller,Karsten"]
[PlyCount "134"]
[EventDate "2011.12.18"]
[EventType "tourn"]
[EventRounds "9"]
[EventCountry "TUR"]
[Source "Chess Today"]
[SourceDate "2011.12.20"]

1. Nf3 d5 2. e3 Nf6 3. b3 g6 4. Bb2 Bg7 5. c4 c6 6. Be2 O-O 7. O-O Bg4 8. d3
Na6 9. Nbd2 Rc8 10. h3 Bxf3 11. Nxf3 Nd7 12. Qd2 Bxb2 13. Qxb2 e6 14. Rac1 Qe7
15. d4 Nc7 16. b4 dxc4 17. Bxc4 Rfe8 18. Rfd1 Nd5 19. a3 N5b6 20. Bb3 Ra8 21.
Ne1 e5 22. Nf3 e4 23. Bc4 Rac8 24. Bb3 Ra8 25. Nd2 a5 26. b5 cxb5 27. Bc2 b4
28. axb4 axb4 29. Nxe4 Nc4 30. Qb3 b5 31. d5 Ra3 32. Qb1 b3 33. Bd3 b2 34. Rc3
Ra1 35. Qc2 Na3 36. Qb3 Rxd1+ 37. Qxd1 b1=Q 38. Bxb1 Nxb1 39. Qxb1 Qxe4 40.
Qxb5 Rb8 41. Qxb8+ Nxb8 42. Rc8+ Kg7 43. Rxb8 Qxd5 44. g3 Qf3 45. Rd8 g5 46.
Rd4 h6 47. h4 Kg6 48. hxg5 hxg5 49. Rd8 Qf6 50. Rd4 Kf5 51. Rb4 Qc3 52. Rd4 f6
53. Kg2 Qc6+ 54. Kg1 Ke5 55. Kh2 Qb6 56. Kg2 f5 {Botvinnik Reloaded  The great
world champion Mikhail Botvinnik reached this position in his analysis of the
adjourned game versus Troianescu (1952) and published his results. Hoang
followed his example:} 57. Kg1 $6 (57. Kf1 $5 {prevents the direct exchange
into a pawn endgame. But Black can win nevertheless:} Qa6+ (57... Qxd4 $2 58.
exd4+ Kxd4 59. Ke2 Ke4 60. f3+ Kd4 61. Kd2 f4 62. g4 $11 {[%csl Gc3,Gd3,Ge3]
Opposition!}) 58. Ke1 Qb5 59. f4+ Kf6 60. fxg5+ Kxg5 61. Rf4 Qd3 62. Kf2 Qd2+
63. Kf3 Qe1 64. e4 fxe4+ 65. Rxe4 Qh1+ 66. Ke3 Qf1 67. Rf4 Qg2 $19) ({Black
can also penetrate after} 57. Rd1 Qc6+ 58. Kg1 Qc4 59. Kg2 Qa4 60. Rd2 Qc6+ 61.
Kh2 Ke4 62. Kg2 f4 63. exf4 gxf4 64. gxf4 Qg6+ 65. Kf1 Kf3 $19 {[%cal Gg6d3]})
57... Qxd4 $1 {The winning procedure as Botvinnik has proved.} 58. exd4+ Kxd4
59. Kf1 (59. Kg2 Kd3 60. Kf3 Kd2 61. g4 f4 62. Ke4 Ke2 63. f3 Kf2 64. Kf5 Kxf3
65. Kxg5 Kg3 $19) 59... Kd3 $1 {The decisive invasion.} 60. Ke1 (60. Kg2 Ke2
61. Kg1 Kd2 (61... f4 $2 62. gxf4 gxf4 63. Kg2 $11) 62. Kh2 Kd1 63. Kh1 f4 64.
gxf4 gxf4 65. Kh2 f3 66. Kh3 Ke1 67. Kg3 Ke2 $19) (60. g4 f4 $19) (60. f4 g4
$19 {[%csl Gd2,Gd3,Ge3,Gf3]}) 60... f4 $1 61. g4 (61. gxf4 {does not help as
Black's king always penetrates to a key square:} gxf4 62. Kf1 (62. f3 Ke3 63.
Kf1 Kxf3 $19 {[%csl Ge3,Gf3,Gg3]}) 62... f3 63. Ke1 Kc2 $19 {[%csl Gc1,Gc2,Gd2,
Ge2]}) (61. Kd1 fxg3 62. fxg3 g4 63. Ke1 Ke3 64. Kf1 Kf3 65. Kg1 Kxg3 $19 {
[%csl Gf3,Gg3,Gh3]}) 61... Kc2 62. Ke2 (62. f3 Kd3 $19 {[%csl Gc2,Gc3,Gd3,Ge3]}
) 62... Kc1 63. Kd3 Kd1 (63... f3 $4 {backfires completely:} 64. Ke4 Kd2 65.
Kxf3 Kd3 66. Kg2 Ke4 67. Kg3 Ke5 68. Kf3 Kd4 69. Ke2 Ke4 70. f3+ Kd4 71. Kd2
$18) 64. Ke4 Ke2 65. Kf5 (65. f3 Kf2 66. Kf5 Kxf3 67. Kxg5 Kg3 $19) 65... Kxf2
66. Kxg5 Kg3 67. Kh5 f3 (67... f3 68. g5 f2 69. g6 f1=Q 70. g7 Qf7+ $19) 0-1

