(1) Ivanchuk,V (2729) - Svidler,P (2765) [D80]
XXIII SuperGM Morelia/Linares MEX/ESP (6), 25.02.2006



1.d4 Nf6 2.c4 g6 3.Nc3 d5 4.Bg5
Psichologically speaking, this is the right choice. Svidler's unpleasant memories from his game against Aronian were fresh still.

4...Ne4 5.Bh4 Nxc3 6.bxc3 dxc4
Deviating from the course of the previous game. The position becomes sharper now.

7.e3 Be6 8.Qb1
[Svidler ha d two recent games with this line, but he had no experience against 8.Qb1 . 8.Nf3 Bg7 9.Rb1 b6 10.Nd2 0-0 11.Be2 c5 12.Bf3 cxd4 13.cxd4 Nd7 14.Bxa8 Qxa8 with excellent compensation for the exchange, Moiseenko-Svidler, Sochi 2005; 8.Rb1 b6 9.Nf3 c6 10.a4 a6 11.e4 b5 12.Be2 Bg7 13.0-0 0-0 14.Ng5 Bc8 15.f4 f6 16.Nf3 f5 and Black managed to stabilise the situation in the centre in Dreev-Svidler, Poikovsky 2005]

8...c5!?
[An interesting novelty, returning the pawn in order to obtain counterplay in the centre. 8...b6 is the normal move, when play can continue with 9.Nf3 Bg7 10.Ng5 Bd5 11.e4 when radicasl changes in the pawn structure are to be expected after 11...h6 ]

9.Qxb7 Bd5 10.Qb5+ Nd7 11.Nf3 Rb8 12.Qa4 cxd4 13.cxd4 Qc8 14.Rc1
#Black has considerably activated his play, but the main problem remains that White's centre is quite solid, which ensures him a strategic advantage in the long run.

14...e6
A double edged decision. Since the fianchetto diagonal is safely blocked by White's centre, Black intends to use his bishop along the a3-f8 diagonal. However, the last move brings to life the h4-bishop too, which will allow White create unpleasant threats with the collaboration of the queen.

15.Bxc4 Rb4 16.Qa6 Bb7 17.Qa5
The pressure against the c4-bishop is neutralised by the concentrated fire against the d8-square.

17...f6
This solves the mentioned problem, but weakens the structure in a chronic way.

18.Nd2 Bxg2 19.Rg1 Qc6
#Although we cannot describe this slightly unusual position with the typical "White has completed his development", we should notice that all his pieces are taking active part to the fight. Which makes Ivanchuk's tactical solution quite logical.

20.Rxg2! Qxg2 21.Bxe6 Bd6 22.Rc8+ Ke7 23.Rxh8 Kxe6 24.Qd8 Qg1+ 25.Ke2 1-0